What is the derivative of #f(t) = (lnt, -3t^3+5t ) #? Calculus Parametric Functions Derivative of Parametric Functions 1 Answer Sonnhard Jul 17, 2018 #dy/dx=-9t^3+5t# Explanation: We have #x(t)=ln(t)# #y(t)=-3t^3+5t# given.So we get #dx/dt=1/t# #dy/dt=-9t^2+5# then #dy/dx=(dy/dt)/(dx/dt)=(-9t^2+5)/(1/t)=-9t^3+5t# Answer link Related questions How do you find the second derivative of a parametric function? How do you find derivatives of parametric functions? How do you find #dy/dx# for the curve #x=t*sin(t)#, #y=t^2+2# ? How do you find the equation of the tangent to the curve #x=t^4+1#, #y=t^3+t# at the point... How do you find #(d^2y)/(dx^2)# for the curve #x=4+t^2#, #y=t^2+t^3# ? How do you find parametric equations of a tangent line? How do you find parametric equations for the tangent line to the curve with the given parametric... How do you find the equation of a line tangent to the curve at point #t=-1# given the parametric... How do you differentiate the following parametric equation: # x(t)=t^3-5t, y(t)=(t-3) #? How do you differentiate the following parametric equation: # x(t)=lnt, y(t)=(t-3) #? See all questions in Derivative of Parametric Functions Impact of this question 1817 views around the world You can reuse this answer Creative Commons License