How do you solve #10x - 7 > 2x + 25#?

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Answer 1 · 2018-07-21T21:35:06

#x > 4#

#10x - 7 > 2x + 25#

Subtract #color(blue)(2x)# from both sides:
#10x - 7 quadcolor(blue)(-quad2x) > 2x + 25 quadcolor(blue)(-quad2x)#

#8x - 7 > 25#

Add #color(blue)7# to both sides:
#8x - 7 quadcolor(blue)(+quad7) > 25 quadcolor(blue)(+quad7)#

#8x > 32#

Divide both sides by #color(blue)8#:
#(8x)/color(blue)8 > 32/color(blue)8#

#x > 4#

This can be said as "#x# is greater than 4."

Hope this helps!

Answer 2 · 2018-07-22T00:10:22

#x>4#

Let's subtract #2x# from both sides to get

#8x-7>25#

Next, add #7# to both sides to get

#8x>32#

Lastly, we divide both sides by #8# to get

#x>4#

Hope this helps!