How do you solve #2x(x-7)(x+4)=0#?

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Answer 1 · 2018-07-22T19:49:07

#x=-4, 0, 7#

Given cubic equation:

#2x(x-7)(x+4)=0#

#2x=0\ \ or\ \ x-7\ \ or \ \ x+4=0#

#x=0\ \ or\ \ \ x=7\ \ \ or \ \ \ x=-4#

#x=-4, 0, 7#

Answer 2 · 2018-07-22T19:58:38

#x=0#, #x=7# and #x=-4#

Let's set all factors equal to zero:

#2x=0=>x=0#

#x-7=0=>x=7#

#x+4=0=>x=-4#

Therefore, our zeroes are at #x=0#, #x=7# and #x=-4#.

Hope this helps!