How do you find the domain & range for 3 Cot(2x)?

1 Answer
Jul 23, 2018

Domain : x in ( -oo, oo ), sans uarr asymptoiic darr x = k(pi/2),
k = 0, +-1, +-2, +-3, ...
Range: y notin ( -1/2, 1/2 )

Explanation:

y = 3 cot 2x = 3 (cos (2x)/sin (2x)) in ( - oo. oo ), ,

x ne zeros of the denominator sin 2x

rArr x ne an integer multiple of (pi/2)

The period

= the common period of sin 2x and cos 2x = (2pi)/2 = pi

See graph. revealing all these aspects:
graph{(y sin (2x) - 3 cos (2x) )= 0[ -10 10 -10 10]}