Question

How do you graph the system of inequalities `x + y <=3` and `x – y <=4`?

Answer 1

See graph and details.

Explanation:

`x + y <= 3 rArr y <= 3 - x and y >= x - 4`. Combining,

`x - 4 <= y < = 3 - x rArr x <= 7/2`.

Graph:
graph{(x+y-3)(x-y-4)(x-7/2)<=0}
The shaded region on the left (`larr`) of x = 7/2, including the

terminal junction `( 7/2, - 1/2)`, is the solution.

O is within. The region on the right is for reversed inequality, in

both.