How do you simplify #sqrt(-32)#?
2 Answers
Jul 25, 2018
Explanation:
Jul 25, 2018
Explanation:
#"using the "color(blue)"law of radicals"#
#•color(white)(x)sqrtaxxsqrtbhArrsqrt(ab)#
#"note that "sqrt(-1)=i#
#sqrt(-32)#
#=sqrt(16xx2xx-1)#
#=sqrt16xxsqrt2xxsqrt(-1)#
#=4xxsqrt2xxi#
#=4isqrt2#