How do you solve for x in #ax = bx -c#?
2 Answers
Jul 27, 2018
Explanation:
#"Collect terms in x on the left side "#
#"subtract "bx" from both sides"#
#ax-bx=-c#
#"take out a "color(blue)"common factor "x#
#x(a-b)=-c#
#"divide both sides by "a-b#
#x=-c/(a-b)#
Jul 28, 2018
Explanation:
If we want to solve for
We now have
Since both terms on the left have an
Lastly, we can divide both sides by
Hope this helps!