How do you simplify (5-3i)^2? Precalculus Complex Numbers in Trigonometric Form Multiplication of Complex Numbers 2 Answers Harish Chandra Rajpoot Jul 28, 2018 16-30i Explanation: Given that (5-3i)^2 =(5-3i)(5-3i) =25-15i-15i+9i^2 =25-30i-9 =16-30i Answer link Kalyanam S. Jul 28, 2018 color(indigo)(=> 16 - 30 i Explanation: (a - b)^2 = a^2 - 2ab + b^2, identity. (5- 3 i)^2 = 5^2 - (2*5*3 i) + (3 i)^2 i^2 = -1 => 25 - 30 i - 9 => 25 - 9 - 30 i color(indigo)(=> 16 - 30 i Answer link Related questions How do I multiply complex numbers? How do I multiply complex numbers in polar form? What is the formula for multiplying complex numbers in trigonometric form? How do I use the modulus and argument to square (1+i)? What is the geometric interpretation of multiplying two complex numbers? What is the product of 3+2i and 1+7i? How do I use DeMoivre's theorem to solve z^3-1=0? How do I find the product of two imaginary numbers? How do you simplify (2+4i)(2-4i)? How do you multiply (-2-8i)(6+7i)? See all questions in Multiplication of Complex Numbers Impact of this question 13957 views around the world You can reuse this answer Creative Commons License