How do you solve the system a+b=11 and 3a-2b=8?
1 Answer
Jul 31, 2018
Explanation:
#a+b=11to(1)#
#3a-2b=8to(2)#
#"from equation "(1)color(white)(x)a=11-bto(3)#
#"substitute "a=11-b" into equation "(2)#
#3(11-b)-2b=8#
#33-3b-2b=8#
#33-5b=8#
#"subtract 33 from both sides"#
#-5b=8-33=-25#
#"divide both sides by "-5#
#b=(-25)/(-5)=5#
#"substitute "b=5" into equation "(3)#
#a=11-5=6#
#"solution is "(a,b)to(6,5)#