How do you find the amplitude, period, and shift for #y = 3 sin(3x- π)#?

1 Answer
Aug 5, 2018

#3,(2pi)/3,pi/3#

Explanation:

#"the standard form of the sine function is"#

#color(red)(bar(ul(|color(white)(2/2)color(black)(y=asin(bx+c)+d)color(white)(2/2)|)))#

#"amplitude "=|a|," period "=(2pi)/b#

#"phase shift "=-c/b," vertical shift "=d#

#"here "a=3,b=3,c=-pi,d=0#

#"amplitude "=|3|=3," period "=(2pi)/3#

#"phase shift "=-(-pi)/3=pi/3#