How do you solve #38+5x >7 (x+4)#?

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Answer 1 · 2016-06-06T05:27:14

#x<5#

#38+5x>7x+28#

#5x-7x> -38+28#

#-2x> -10#

#2x<10#

#x<5#

Answer 2 · 2018-08-10T02:32:39

#x<5#

First, let's switch the sides:

#7(x+4)<5x+38#

Next, we can distribute the #7# on the left to get

#7x+28<5x+38#

Next, subtract #5x# from both sides to get

#2x+28<38#

We can subtract #28# from both sides to get

#2x<10#

Lastly, we divide both sides by #2# to get

#x<5#

Hope this helps!