How do you graph h(x)= -5/3 absx + 6?

1 Answer
Aug 10, 2018

See explanation and angle-shaped graph.

Explanation:

Here,

abs x = 3/5( 6 - h ) >=0 rArr h <= 6. Use, y for h.

Socratic inverted V graph is immediate.
graph{(abs (x) -0.6(6-y))(y-6+0x)=0[-16 16 -8 8]}

The vertex is ( 0, 6 ). You can see the graph, with h <= 6.

If you change abs x to x, the graph would be as shown below.
graph{(x - 0.6(6-y))(x+0.6(6-y))=0[-10 20 0 15]}

For this, the equation is (x-0.6(6-h)(x+0.6(6-h)) = 0,

for the whole patr of straight lines..