How do you simplify #(7-6i)(5-i)#?

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Answer 1 · 2018-08-12T05:41:36

#29 - 37i#

#(7-6i)(5-i)#

Use FOIL to distribute/expand:
#7 * 5 = 35#

#7 * -i = -7i#

#-6i * 5 = -30i#

#-6i * -i = 6i^2#

Combine them together:
#35 - 7i - 30i + 6i^2#

Combine like terms:
#35 - 37i + 6i^2#

We know that #i^2 = -1#, so:

#35 - 37i + 6(-1)#

#=35 - 37i - 6#

#=29 - 37i#

Hope this hleps!