How do you simplify #sqrt(-24) #? Precalculus Complex Numbers in Trigonometric Form Multiplication of Complex Numbers 1 Answer Shantelle Aug 12, 2018 #2isqrt6# Explanation: #sqrt(-24)# #=sqrt(-1*24)# We know that #i = sqrt(-1)#, so: #i*sqrt24# #=i*sqrt(4*6)# #=i*2sqrt6# #=2isqrt6# Hope this helps! Answer link Related questions How do I multiply complex numbers? How do I multiply complex numbers in polar form? What is the formula for multiplying complex numbers in trigonometric form? How do I use the modulus and argument to square #(1+i)#? What is the geometric interpretation of multiplying two complex numbers? What is the product of #3+2i# and #1+7i#? How do I use DeMoivre's theorem to solve #z^3-1=0#? How do I find the product of two imaginary numbers? How do you simplify #(2+4i)(2-4i)#? How do you multiply #(-2-8i)(6+7i)#? See all questions in Multiplication of Complex Numbers Impact of this question 7317 views around the world You can reuse this answer Creative Commons License