What is the vertex of #y=2 (x-3)^2+4#?
1 Answer
Aug 12, 2018
Explanation:
#"the equation of a parabola in "color(blue)"vertex form"# is.
#•color(white)(x)y=a(x-h)^2+k#
#"where "(h,k)" are the coordinates of the vertex and a"#
#"is a multiplier"#
#y=2(x-3)^2+4" is in this form"#
#"vertex "=(3,4)#
#"since "a>0" then minimum turning point "uuu#
graph{2(x-3)^2+4 [-10, 10, -5, 5]}
