#2CO(g) + O_2(g) -> 2CO_2(g)#. How many liters of #O_2# will react with 74.2 liters of CO? If 6.5 g of CO react, how many liters of #CO_2# are produced?
37.1 L of
5.20 L of
We calculate the relative quantities from the molar ratios in the balanced reaction equation.
As a pretty good approximation, gas volumes are proportional to molar amounts. Therefore with a molar ratio of 2:1 of
Similarly, converting the CO mass to moles, we have
This is approximately 22.4L /mol * 0.232 moles = 5.20 L at “STP” - slightly more a “NTP”.
This would produce the same molar and volumetric amount of