4 gms of hydrogen are ignited with 4 gms of oxygen. the weight of water formed ?

1 Answer
May 22, 2017

"Mass"~=4.5*g

Explanation:

We need (i), a stoichiometric equation,

H_2(g) + 1/2O_2(g) rarr H_2O(l).

We have (4*g)/(32.0*g*mol^-1)=1/8*mol "dioxygen gas".

And (4*g)/(2.0*g*mol^-1)=2*mol "dihydrogen gas".

Clearly, the "dioxygen gas" is present in DEFICIENCY, and O_2 is the limiting reagent.

Given the equation, we can make at most 1/4*mol of water, i.e. a mass of 1/4*cancel(mol)xx18.01*g*cancel(mol^-1)=??*g