4 gms of hydrogen are ignited with 4 gms of oxygen. the weight of water formed ?

1 Answer
May 22, 2017

Answer:

#"Mass"~=4.5*g#

Explanation:

We need (i), a stoichiometric equation,

#H_2(g) + 1/2O_2(g) rarr H_2O(l)#.

We have #(4*g)/(32.0*g*mol^-1)=1/8*mol# #"dioxygen gas"#.

And #(4*g)/(2.0*g*mol^-1)=2*mol# #"dihydrogen gas"#.

Clearly, the #"dioxygen gas"# is present in DEFICIENCY, and #O_2# is the limiting reagent.

Given the equation, we can make at most #1/4*mol# of water, i.e. a mass of #1/4*cancel(mol)xx18.01*g*cancel(mol^-1)=??*g#