500.0 mL of a gas is collected at 745.0 mm Hg. What will the volume be at standard pressure?

1 Answer
Apr 6, 2016

Answer:

This is an application of Boyle's Law.

Explanation:

#P_1V_1 = P_2V_2#. This form is useful in that we do not have to convert volume and pressure to standard forms. We can even use the non-standard pressure measurement of #mm# #Hg#.

#1# #atm# #=# #760# #mm# #Hg#. So the volume of your gas should slightly reduce:

#V_2 = (P_1xxV_1)/(P_2)# #=# #(745*mm*Hgxx500.0*mL)/(760*mm*Hg)# #=# #??# #mL#.

Note that here (reasonably) a constant temperature is assumed.