# Question #2a65a

##### 1 Answer

To determine the bond order, you subtract the antibonding electrons from the bonding electrons and divide by 2.

The formula for bond order is

Bond Order = ½(*b* - *a*)

where *b* is the number of bonding electrons and *a* is the number of antibonding electrons.

You first draw the molecular orbital diagram for the molecule. Let’s use C₂ as an example.

You put the eight valence electrons in the lowest orbitals:

You have six bonding and two antibonding electrons. The bond order is

Bond Order = ½(*b* - *a*), = ½(6 – 2) = ½ × 4 = 2

*EXAMPLE*:

Calculate the bond order in C₂²⁺.

*Solution*:

Here we have only six valence electrons. They are in the

Bond Order=½(*b* - *a*), = ½(4 – 2) = ½ × 2 = 1