Question #104c1

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Question #104c1

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Answer 1 · 2015-02-11T00:42:15

A 10X TBE solution is 10 times as concentrated as a 1X TBE solution, which means that you must dilute it 10-fold to get it to match a 1X TBE solution.

Since the solution will have various components of different molarities, $X$ $"X"$ is used to illustrate a concentrated solution - 1X, 5X, 10X, 100X, and so on.

This is usefull when you're not concerned about the individual components of the solution, but rather about how concentrated or diluted a solution is.

So, you're basically dealing with a dilution calculation

$C_{1} V_{1} = C_{2} V_{2}$ $C_1V_1 = C_2V_2$

In you case, you'll get

$10X TBE \cdot 10 mL = 1X TBE \cdot V_{final}$ $"10X TBE" * "10 mL" = "1X TBE" * V_("final")$

$V_{final} = \frac{10X}{1X} \cdot 10 mL = 100 mL$ $V_("final") = "10X"/"1X" * "10 mL" = "100 mL"$

This will be the final volume of the solution, which means that the volume of buffer you must add is

$V_{buffer} = V_{final} - 10 mL = 100 - 10 = 90 mL$ $V_("buffer") = V_("final") - "10 mL" = 100 - 10 = "90 mL"$

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Question #104c1

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