# What volume of water would you add to 15.00 mL of a 6.77 M solution of nitric acid in order to get a 1.50 M solution?

##### 1 Answer

May 1, 2014

This dilution problem uses the equation

(6.77 M) (15.00 mL) = (1.50 M)(15.00 mL + x )

101.55 M mL= 22.5 M mL + 1.50x M

101.55 M mL - 22.5 M mL = 1.50x M

79.05 M mL = 1.50 M

79.05 M mL / 1.50 M = x

52.7 mL = x

59.7 mL needs to be added to the original 15.00 mL solution in order to dilute it from 6.77 M to 1.50 M.

I hope this was helpful.

SMARTERTEACHER