# How do you calculate concentration from titration?

${M}_{A} {V}_{A}$ = ${M}_{B} {V}_{B}$

Let's assume you are titrating a strong acid (10 mL unknown concentration HCl) with a strong base (1.0 M NaOH). It takes 25mL of NaOH to neutralize the acid. If you solve for ${M}_{A}$ you will see that

${M}_{A}$ = (${M}_{B} {V}_{B}$) / ${V}_{A}$

or ${M}_{A}$ = (1.0M x 25mL) / 10

${M}_{A}$ = 2.5M HCl

This works because M = moles/L

*Note: You do not need to convert volumes of acid and base to liters as long as both are expressed in same unit (mL).