# Question 8bd13

Mar 22, 2015

You should dilute your original solution to a total volume of $\text{2000 mL}$.

Here's how you should think about dilution calculations. Your original solution, the one you want to dilute, contains a certain amount of moles of solute - in your case, sulfuric acid.

When you dilute a solution, that certain number of moles of solute does not change, it remains constant. What changes is the concentration of the solution.

That happens because you'll have the same amount of solute in a bigger volume of solution.

That is what the formula for dilution calculations actually expresses

${C}_{1} {V}_{1} = {C}_{2} {V}_{2}$, where

${C}_{1}$, ${V}_{1}$ - the concentration and volume of the initial solution;
${C}_{2}$, ${V}_{2}$ - the concentration and volume of the final solution.

Plug your data into this equation and you'll get

V_2 = C_1/C_2 * V_1 = ("11"cancel("M"))/("0.17"cancel("M")) * "30 mL" = "1941.2 mL"#

Rounded to one sig fig, the number of sig figs given for 30 mL, answer will be

${V}_{2} = \textcolor{red}{\text{2000 mL}}$