Question

Question #9140f

Answer 1

37.5 litres of `C_2H_2` is required and 37.5 litres of water vapour is produced.

`2C_2H_(2(g))+5O_(2(g))rarr4CO_(2(g))+2H_2O_((g))`

From the equation you can see that if 75.0L of `CO_2` is produced then 75/2 = 37.5L of `C_2H_2` is required since 1 mole `C_2H_2` produces 2 mole `CO_2`.

2 moles `C_2H_2` produces 2 moles `H_2O`.

So 37.5L `C_2H_2` produces 37.5L `H_2O` vapour.