Question #95958

1 Answer
Jul 3, 2015

Answer:

You can see by the equation that every mole of silver nitrate "needs" half a mole of copper.

Explanation:

What we need to do is divide the grams of #AgNO_3# by its molar mass to find the number of moles of #AgNO_3#, and then divide this by #2#.

#m_m(AgNO_3)=107.9+14.0+3*16.0=169.9g//mol#

Example:
100 grams of #AgNO_3# would be:

#100/169.9mol->1/2*100/(169.9)molCu# would be needed.

(or a net division by 339.8)