# Question 1084c

Sep 12, 2015

Use water's density.

#### Explanation:

You measured the mass of the water to be equal to 17.97 g, which means that you can use water's density at the temperature at which you did the measurements to figure out th volume that sample would occupy.

Density is defined as mass per unit of volume

$\rho = \frac{n}{V}$

Assuming that you did the measurements at ${20}^{\circ} \text{C}$, you have the density of equal equal to $\text{0.9982071 g/mL}$.

http://antoine.frostburg.edu/chem/senese/javascript/water-density.html

The theoretical volume of the sample would be

17.97color(red)(cancel(color(black)("g"))) * "1 mL"/(0.9982071color(red)(cancel(color(black)("g")))) = "18.002 mL"

To get the percent error, use the formula

$\textcolor{b l u e}{\text{% error" = (|"measured value" - "theoretical value"|)/"theoretical value} \cdot 100}$

"% error" = (|(20.00 - 18.002)|color(red)(cancel(color(black)("mL"))))/(18.002color(red)(cancel(color(black)("mL")))) * 100
"% error" = 1.998/18.002 * 100 = color(green)("11.10 %")#