# Question #cfc54

Sep 17, 2015

You will need the concentration of the stock solution of disinfectant!

#### Explanation:

This is a dilution question where it can be solved as follows.

The number of mole of the disinfectant in a $V$ volume of the stock solution (we will call it) ${n}_{s}$ is equal to the number of mole of the disinfectant in 2.00 L of the hand-soap solution (we will call it) ${n}_{h}$.

This would give us: ${n}_{s} = {n}_{h}$

In general, the number of mole $n$ is related to the concentration by $n = C \times V$ where $C$ is the concentration and $V$ is the volume.

Therefore, ${C}_{s} \times {V}_{s} = {C}_{h} \times {V}_{h}$

${C}_{h} = 0.400 \text{mol/L} \mathmr{and} {V}_{h} = 2.00 L$

To calculate the volume of the disinfectant ${V}_{s} = \frac{{C}_{h} \times {V}_{h}}{C} _ s$ you will need the value of ${C}_{s}$ which is the concentration of the disinfectant stock solution.