# Question #607b1

##### 1 Answer

#### Answer:

#### Explanation:

So, you know that the gas is *sealed* in a container. This will tell you two important things

*the amount of gas remains unchanged*;*the volume of the container remains unchainged*

Now, the idea here is that the pressure of a gas is **proportional** to its temperature *if* volume and number of moles, which represents the amount of gas, remain **constant** - this is known as Gay Lussac's Law.

This means that if you *increase* the temperature of the gas, its pressure will increase as well. Likewise, if you *decrease* the temperature, its pressure will decrease as well.

In your case, you know that the temperature is **increased** from

Mathematically, Gay Lussac's Law is written like this

#P_1/T_1 = P_2/T_2" "# , where

Plug in your value to get

#P_2 = T_2/T_1 * P_1#

#P_2 = (475color(red)(cancel(color(black)("K"))))/(298color(red)(cancel(color(black)("K")))) * "111 kPa" = "176.93 kPa"#

You need to round the answer to three sig figs

#P_2 = color(green)("177 kPa")#