# Question eae13

Nov 14, 2015

The pressure will increase to $\text{5.63 atm}$.

#### Explanation:

Use Gay-Lussac's law, which states that when the volume of a gas is kept constant, its volume and pressure are directly proportional. The equation for this gas law is ${P}_{1} / {T}_{1} = {P}_{2} / {T}_{2}$.

${P}_{1} = \text{5.00 atm}$
${T}_{1} = \text{5.00"^"o""C"+273.15="278.15 K}$
P_2=???
${T}_{=} \text{40.0"^"o""C"+273.15="313.15 K}$

Solution
Rearrange the equation to isolate ${P}_{2}$ and solve.

${P}_{2} = \frac{{P}_{1} {T}_{2}}{T} _ 1$

P_2=((5.00"atm") * (313.15"K"))/(278.15"K")="5.63 atm"#