Question #17e71
1 Answer
Explanation:
The new concentration is actually given to you,
You know that you when dilute a solution, you essentially keep the number of moles of solute constant and increase the volume of the solution.
Now, you know that your stock solution has a concentration of
#c = n/V implies n = c * V#
#n = 6.00"moles"/color(red)(cancel(color(black)("L"))) * 20.0 * 10^(-3)color(red)(cancel(color(black)("L"))) = "0.120 moles HCl"#
Now the question is what volume of the target solution would contain the same number of moles of
#c = n/V implies V = n/c#
#V = (0.120color(red)(cancel(color(black)("moles"))))/(1.50color(red)(cancel(color(black)("moles")))/"L") = "0.080 L"#
Convert this to mililiters to get
#V = 0.080color(red)(cancel(color(black)("L"))) * "1000 mL"/(1color(red)(cancel(color(black)("L")))) = color(green)("80.0 mL")#
So, to prepare this solution, you would take the