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Answer 1 · 2015-12-01T23:50:46

#sp^2#

carbon have 6 # e^-#

#=>#

#1s^(2)2s^(2)2p^2# in normal state following klechkowski rule

#1s^(2)2s^(2)2p_x^(1)2p_y^(1)2p_z^0# you can see the orbital #2p_z# have no electron

So the orbital #2s^2# give one electron this is called the hybridization state

you have now #sp^3# hybridization

BUT, to form double liaison you need #pi# electron

#pi# electron don't match with hybridization state, so the orbital #2p_z# get out

so finally you have #sp^2#

#---------------------#

You can done this without any complication using the VSEPR Theory

Here the carbon is : #AX_3# which means it's #sp^2#