As per eqn: CH4 +2O2 ----> CO2 + 2H2O, 1 mole or 44g CO2 is produced from 16 g methane.So 0.44 g Co2 will be obtained from 0.16 g methane. So 9.6 g sample contains 0.16g methane.
Hence% of purity is 0.16X100/9.6 = 1.67
To determine the percent purity, first determine the balanced chemical reaction for the combustion of methane:
Then, determined the amount of
Then to calculate the percent purity, divide the actual yield of