Question #d755f

1 Answer
Feb 17, 2016

375 mL of water is needed.

Explanation:

Using the dilution formula, calculate first for the amount of 2.0 M NaOH needed to prepare 500 mL of 0.5M NaOH solution:

let:
C_1= initial concentration of NaOH solution
C_2= final concentration of NaOH solution
V_1 = volume needed
V_2 = total volume of resulting solution

So then:

C_1V_1=C_2V_2
V_1=(C_2V_2)/(C_1)

V_1=(color(blue)cancel(0.5 M)(500 mL))/color(blue)cancel(2.0 M)

V_1= 125 mL

Then to calculate for the volume of water needed, subtract the volume of the final solution with the computed volume of 2.0 M NaOH needed:

V_(water)= 500 mL - 125 mL
V_(water)= 375 mL