Question

How many grams of lithium metal are required to react with a `28*g` mass of dinitrogen gas?

Answer 1

`6Li(s) + N_2(g) rarr 2Li_3N(s)`

Explanation:

Lithium is one of the few metals that will react with nitrogen gas directly at room temperature. Lithium nitride is one VERY expensive way to produce ammonia gas:

`Li_3N(s) + 3H_2O(l) rarr NH_3(aq) + 3LiOH(aq)`

So, given the stoichimetry, 42 g of lithium metal are required to react with 28 g of dinitrogen gas.