What is the concentration of #1.12*L# of carbon dioxide gas?

1 Answer
Apr 25, 2016

Answer:

Approx. #0.9*mol*L^-1#

Explanation:

#CaCO_3(s) + 2HCl(aq) rarr CaCl_2(aq) + H_2O(l) + CO_2(g)uarr#

We assume that the gas was collected at #298*K# and at #1# #atm# pressure. Under these conditions, #1# #mol# of gas, any gas, has a volume of #25.4*L#

So moles of #CO_2# #=# #(1.12*cancelL)/(25.4*cancelL*mol^-1)# #=# #4.41xx10^-2*mol#

Now form the stoichiometric equation, for each mole of gas produced, there were 2 mole of hydrochloric acid.

Thus #"Concentration"# #=# #(2xx4.41xx10^-2*mol)/(0.100*L)# #=# #??*mol*L^-1#

This is a slight over estimate in that the gas collected is saturated with water vapour. This saturated vapour pressure should be subtracted from the pressure.