# Question #cb195

$\left[{H}_{3} {O}^{+}\right] = \left[O {H}^{-}\right] = {10}^{- 7} M$ is a neutral solution. With higher $\left[{H}_{3} {O}^{+}\right]$ you have $\left[O {H}^{-}\right]$ and an acidic solution. With lower $\left[{H}_{3} {O}^{+}\right]$ you get higher $\left[O {H}^{-}\right]$ and you have a basic solution.