# Question #1c2bd

##### 1 Answer

#### Answer:

#### Explanation:

Before the force is applied we know

#"momentum" = "mass" times "velocity" = "10 kg m/s"#

Since mass in the above is

We can now work out kinetic energy, KE:

#KE=1/2mv^2=1/2*5*2^2="10 J"#

The force of

#F=(mv-"mu")/t=m * (v-u)/t#

Where

So

#0.2 = 5 * ((v-2))/10#

rearranging helps us find

#2 = 5 * (v-2)#

#2/5 = v-2#

#v = 12/5" ms"^(-1)#

Hence final kinetic energy,

#KE = 1/2mv^2 = 1/2 * 5 * (12/5)^2 = "14.4 J"#

So the overall change in

#Delta_"KE" = 14.4 - 10 = "4.4 J"#