# rho_"glycerol"=1.20*g*mL^-1. What volume is associated with a 43.7*g mass?

May 23, 2016

Approx. $36 \cdot m L$

#### Explanation:

$\text{Density, } \rho$ $=$ $\text{Mass"/"Volume}$

Thus $\text{Volume}$ $=$ $\frac{\text{Mass}}{\rho}$

$=$ $\frac{43.7 \cdot g}{1.20 \cdot g \cdot m {L}^{-} 1}$ $=$ ??mL.

Note that this answer is consistent dimensionally. We were asked to find a volume. We got an answer in $m L$, which is an internal check that we have made the right calculation.

As you can see, ${\rho}_{\text{glycerol}}$ is greater than ${\rho}_{\text{water}}$. Glycerol is a sticky and viscous liquid; it is also infinitely soluble in water. Can you suggest a reason why glycerol should have these properties?