# A leg of a 45-45-90 triangle has length 3sqrt2. What's the length of the hypotenuse?

Multiply the length of the leg by $\sqrt{2}$ to arrive at the length of the hypotenuse = 6.
45-45-90 triangles have a ratio of bases to hypotenuse of $1 : \sqrt{2}$
We are given that a leg of a 45-45-90 triangle has a length of $3 \sqrt{2}$. To find the hypotenuse, we multiply the length of the leg by $\sqrt{2}$:
$3 \sqrt{2} \cdot \sqrt{2} = 3 \cdot 2 = 6$