# Question d6aae

Sep 6, 2016

42.4%

#### Explanation:

Let an object of mass $m$ has initial momentum ${p}_{i}$
Kinetic energy $K {E}_{i} = \frac{1}{2} {p}_{i}^{2} / m$
After collision let final momentum be ${p}_{f}$
Therefore kinetic energy $K {E}_{f} = \frac{1}{2} {p}_{f}^{2} / m$ and
Where $= {p}_{f}$ is Final momentum.
Using given % age of kinetic energy we have

18%" of "KE_i=KE_f
$\implies 0.18 \times \frac{1}{2} {p}_{i}^{2} / m = \frac{1}{2} {p}_{f}^{2} / m$
$\implies 0.18 \times {p}_{i}^{2} = {p}_{f}^{2}$
Taking square root of both sides we get
$0.424 \times {p}_{i} = {p}_{f}$, rounded to three decimal places
Momentum is 42.4%#