Question #59798

1 Answer
Jun 8, 2016

Answer:

#E_2 = 0.27#[J]

Explanation:

Just before the strike

#m g h_1 = E_1 = 0.75#[J] then

#mg = 0.75/h_1 = 0.75/0.8#

After the strike the ball needs kinetic energy #E_2# to attain #0.45#[m]

so we have

#h_2 mg = E_2# or

#E_2 = 0.45xx 0.75/0.8 = 0.27#[J]