Question #b4813

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Question #b4813

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Answer 1 · 2017-12-20T08:43:41

$[X e] 4 f^{14} 5 d^{10} 6 s^{2} 6 p^{2}$ $[Xe] 4f^(14) 5d^(10) 6s^(2) 6p^(2)$

Explanation:

Xenon has an atomic number of 54 and we can use it to shorten our electron configuration.

If you are interested in the configuration written out in full, it is the following:

$1 s^{2} 2 s^{2} 3 s^{2} 3 p^{6} 3 d^{10} 4 s^{2} 4 p^{6} 4 d^{10} 5 s^{2} 5 p^{6} 4 f^{14} 5 d^{10} 6 s^{2} 6 p^{2}$ $1s^2 2s^2 3s^2 3p^6 3d^10 4s^2 4p^6 4d^10 5s^2 5p^6 4f^14 5d^10 6s^2 6p^2$

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Question #b4813

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