# Question #38dd4

Aug 8, 2016

$y + 2 = \frac{3}{5} \left(x - 10\right)$

#### Explanation:

The equation of a line in $\textcolor{b l u e}{\text{point-slope form}}$ is.

$\textcolor{red}{| \overline{\underline{\textcolor{w h i t e}{\frac{a}{a}} \textcolor{b l a c k}{y - {y}_{1} = m \left(x - {x}_{1}\right)} \textcolor{w h i t e}{\frac{a}{a}} |}}}$
where m represents the slope and $\left({x}_{1} , {y}_{1}\right) \text{ a point on the line}$

here $m = \frac{3}{5} \text{ and } \left({x}_{1} , {y}_{1}\right) = \left(10 , - 2\right)$

substitute these values into the equation.

$\Rightarrow y - \left(- 2\right) = \frac{3}{5} \left(x - 10\right)$

Thus $y + 2 = \frac{3}{5} \left(x - 10\right) \text{ is equation in point-slope form}$

By expanding the bracket and collecting like terms we also get

$y + 2 = \frac{3}{5} x - 15 \Rightarrow y = \frac{3}{5} x - 17$ in slope-intercept form.