Question #38dd4
1 Answer
Aug 8, 2016
Explanation:
The equation of a line in
#color(blue)"point-slope form"# is.
#color(red)(|bar(ul(color(white)(a/a)color(black)(y-y_1=m(x-x_1))color(white)(a/a)|)))#
where m represents the slope and# (x_1,y_1)" a point on the line"# here
#m=3/5" and " (x_1,y_1)=(10,-2)# substitute these values into the equation.
#rArry-(-2)=3/5(x-10)# Thus
#y+2=3/5(x-10)" is equation in point-slope form"# By expanding the bracket and collecting like terms we also get
#y+2=3/5x-15rArry=3/5x-17# in slope-intercept form.