# Question #7ef8b

Jul 14, 2016

No solution

#### Explanation:

If we substitute $x = 2 y - 3$ from the first equation into the second equation, we get

$2 y - 3 = 2 y + 4$

subtracting $2 y$ from each side of the equation then gives us

$- 3 = 4$

a contradiction. Thus there is no $\left(x , y\right)$ pair such that both equations hold.