# How do you solve x-2y=-2 and x-2y=3 by graphing?

For $x - 2 y = - 2$ set first $x$ and then $y$ equal to zero to establish intercept points:
$\left(0 , 1\right)$ and $\left(- 2 , 0\right)$
Similarly for $x - 2 y = 3$ find the intercept points as
$\left(0 , - 1 \frac{1}{2}\right)$ and $\left(3 , 0\right)$