Question #33da5

1 Answer
Aug 18, 2016

Answer:

An aqueous solution for which #[HO^-]=4.2xx10^-8*mol*L^-1# is slightly acidic.

Explanation:

For neutrality under standard conditions #[H_3O^+]=[HO^-]=10^-7*mol*L^-1#.
Alternatively since, #pH+pOH =14#, where #pH=-log_10[H_3O^+]#, if #pH<7#, then the solution is acidic.

Here #pOH=7.38#, thus #pH=6.62#.