Question

How do we factorize `9+3a+19b`?

Answer 1

`9+3a+19b` cannot be factorized.

Explanation:

Let us consider the three terms.

`9=3×3`

`3a=3×a`

`19b=19×b`

It is observed that none of the factor is common to all the three monomials.

Hence, `9+3a+19b` cannot be factorized.

Note: Had it been `9+3a+9b`, as `9b=3×3×b`, there is a common factor `3` and we could have factorized `9+3a+9b` as `3×(3+a+3b)` and two factors would be `3` and `3+3a+3b`.