# How do we factorize 9+3a+19b?

May 5, 2017

$9 + 3 a + 19 b$ cannot be factorized.

#### Explanation:

Let us consider the three terms.

9=3×3

3a=3×a

19b=19×b

It is observed that none of the factor is common to all the three monomials.

Hence, $9 + 3 a + 19 b$ cannot be factorized.

Note: Had it been $9 + 3 a + 9 b$, as 9b=3×3×b, there is a common factor $3$ and we could have factorized $9 + 3 a + 9 b$ as 3×(3+a+3b) and two factors would be $3$ and $3 + 3 a + 3 b$.