How do we factorize #9+3a+19b#?

1 Answer
May 5, 2017

Answer:

#9+3a+19b# cannot be factorized.

Explanation:

Let us consider the three terms.

#9=3×3#

#3a=3×a#

#19b=19×b#

It is observed that none of the factor is common to all the three monomials.

Hence, #9+3a+19b# cannot be factorized.

Note: Had it been #9+3a+9b#, as #9b=3×3×b#, there is a common factor #3# and we could have factorized #9+3a+9b# as #3×(3+a+3b)# and two factors would be #3# and #3+3a+3b#.