How many grams of dihydrogen gas are required to produce a #10.53*g# mass of ammonia?

1 Answer
Sep 11, 2016

Answer:

Almost #2*g# of dihydrogen gas are required.

#1/2N_2(g) + 3/2H_2(g) rarr NH_3(g)#

Explanation:

We follow the given stoichiometric equation, which explicitly states that #14*g# dinitrogen gas react with #3.0*g# dihydrogen to give #17*g# ammonia.

#"Moles of ammonia"# #=# #(10.53*g)/(17.03*g*mol^-1)# #=# #0.618*mol#

And thus #3/2xx0.618*molxx2.0159*g*mol^-1" dihydrogen"# are required.