How many grams of dihydrogen gas are required to produce a 10.53g mass of ammonia?

1 Answer
Sep 11, 2016

Almost 2g of dihydrogen gas are required.

12N2(g)+32H2(g)NH3(g)

Explanation:

We follow the given stoichiometric equation, which explicitly states that 14g dinitrogen gas react with 3.0g dihydrogen to give 17g ammonia.

Moles of ammonia = 10.53g17.03gmol1 = 0.618mol

And thus 32×0.618mol×2.0159gmol1 dihydrogen are required.