Question

Question #cf6c6

Answer 1

See a solution process below:

Explanation:

Equation 1: Solve for two points which solve the first equation and plot these points:

First Point:

For `x = 0`

`y = 0 - 2`
`y = -2` or `(0, -2)`

Second Point:

For `x = 2`

`y = 2 - 2`
`y = 0` or `(2, 0)`

We can plot the two points on the coordinate plane and draw a line through them to graph the line:

graph{(y-x+2)(x^2+(y+2)^2-0.03)((x-2)^2+y^2-0.03)=0 [-15, 15, -7.5, 7.5]}

Equation 2: Solve for two points which solve the second equation and plot these points:

First Point:

For `x = 0`

`y = (-2 * 0) + 7`
`y = 0 + 7`
`y = 7` or `(0, 7)`

Second Point:

For `x = 2`

`y = (-2 * 2) + 7`
`y = -4 + 7`
`y = 3` or `(2, 3)`

We can plot the two points on the coordinate plane and draw a line through them to graph the line:

graph{(y+2x-7)(x^2+(y-7)^2-0.05)((x-2)^2+(y-3)^2-0.05)(y-x+2)(x^2+(y+2)^2-0.05)((x-2)^2+y^2-0.05)=0 [-15, 15, -7.5, 7.5]}

Solution:

We can see from the graph, the lines cross at `(3. 1)`:

graph{((x-3)^2+(y-1)^2-0.05)(y+2x-7)(y-x+2)=0 [-10, 10, -2.5, 7.5]}