Question #28493

1 Answer
Feb 24, 2017

Answer:

(a) #-1.bar81#
(b) #-2#
(c) #-0.bar8#

Explanation:

(a) Given #V=IR#
For #R=1,# #I=2/1=2A#
For #R=1.1,# #I=2/1.1=1.bar81A#
#:.# the average rate of change of #I# with respect to #R# in the interval of interest is#=(2-1.bar81)/(1-1.1)=-1.bar81#

(b) #I=V/R#
#=>I=2/R#
To find rate of change we differentiate function #I# with respect to Resistance #R#.
#(dI)/(dR)=2xx(-1)R^-2#
#=>(dI)/(dR)=-2R^-2#
ROC at #R=1Omega#
#(dI)/(dR)|_1=-2xx(1)^-2#
#=>(dI)/(dR)=-2#

(c) #R=V/I#
#=>R=2/I#
To find rate of change we differentiate function #R# with respect to Current #I#
#=>(dR)/(dI)=-2I^-2#
ROC at #I=1.5A#
#(dR)/(dI)|_1.5=-2xx(1.5)^-2#
#(dR)/(dI)=-0.bar8#